On 2009-12-24, Mariusz Marszałkowski <m...@g...com> wrote:
> Heya
>
> Jak zrobić w bashu pod windows coś, co w C wygląda tak:
>
> int i = 0;
>
> const char *param1[] = {"text1","text2","text3",....,"textN"};
> const char *param2[] = {"dupa1","dupa2","dupa3",....,"dupaN"};
>
> while( i< sizeof(param1)/sizeof(param1[0]) ) {
> printf("polecenie_1 %s %s \n",param1[i],param2[i]);
> printf("polecenie_2 %s %s \n",param1[i],param2[i]);
> printf("polecenie_3 %s %s \n",param1[i],param2[i]);
> i++;
> }
>
> Dziękuję z góry i pozdrawiam

man bash /arrays
man bash /arithmetic evaluation
help for

#v+
#!/usr/bin/env bash

param1=(bim1 bim2 bim3 bimN)
param2=(bom1 bom2 bom3 bomN)

echo ${#param1[@]}
echo ${#param2[@]}

for (( i=0; i < ${#param1[@]}; ++i )) ; do
echo polecenie_1 ${param1[$i]} ${param2[$i]}
echo polecenie_2 ${param1[$i]} ${param2[$i]}
echo polecenie_3 ${param1[$i]} ${param2[$i]}
done
#v-

--
Pozdrawiam,
Lech Lorens - lp.pw@snerol_hcel