Re: Ostatni krok Achillesa - Grupy dyskusyjne w eGospodarka.pl

eGospodarka.pl › Grupy › pl.sci.inzynieria › Ostatni krok Achillesa › Re: Ostatni krok Achillesa

Path: news-archive.icm.edu.pl!news.rmf.pl!news.icm.edu.pl!newsfeed.pionier.net.pl!new
s.gazeta.pl!not-for-mail
From: "Robakks" <R...@g...pl>
Newsgroups: pl.sci.filozofia,pl.sci.inzynieria
Subject: Re: Ostatni krok Achillesa
Date: Tue, 13 Apr 2010 18:58:10 +0200
Organization: "Portal Gazeta.pl -> http://www.gazeta.pl"
Lines: 7
Message-ID: <hq27r8$4vf$1@inews.gazeta.pl>
References: <hpc1um$4fk$1@inews.gazeta.pl> <hpccur$840$1@inews.gazeta.pl>
<hpen8a$ct6$1@inews.gazeta.pl> <hperlj$scg$1@inews.gazeta.pl>
<hpevde$c3i$1@inews.gazeta.pl> <hpfc3i$sse$1@inews.gazeta.pl>
<hpg1tn$itn$1@inews.gazeta.pl> <hpg2vc$mnu$1@inews.gazeta.pl>
<hpjvrs$nnc$1@inews.gazeta.pl> <hpkvdf$e7h$1@inews.gazeta.pl>
<hpmont$b6a$1@inews.gazeta.pl> <hpnrq1$ku9$1@inews.gazeta.pl>
<hpo22p$frq$1@inews.gazeta.pl> <hprk44$g93$1@inews.gazeta.pl>
<hpsfe9$fl6$1@inews.gazeta.pl> <hpsgu5$lcl$1@inews.gazeta.pl>
<hpsil5$reg$1@inews.gazeta.pl> <hpsj1q$sno$1@inews.gazeta.pl>
<hpsjeg$s5$1@inews.gazeta.pl> <hpsksb$5o4$1@inews.gazeta.pl>
<hpspen$m1m$1@inews.gazeta.pl> <hpt0ga$j4g$1@inews.gazeta.pl>
<hpt6ee$dtt$1@inews.gazeta.pl> <hpt784$hb6$1@inews.gazeta.pl>
<hpuh31$lgd$1@inews.gazeta.pl> <hpuip4$rf8$1@inews.gazeta.pl>
<hpuod6$iko$1@inews.gazeta.pl> <hpuqjc$qec$1@inews.gazeta.pl>
<hq183a$b1t$1@inews.gazeta.pl> <hq1aes$jki$1@inews.gazeta.pl>
<hq26bj$t4k$1@inews.gazeta.pl>
NNTP-Posting-Host: chello089073079001.chello.pl
Mime-Version: 1.0
Content-Type: text/plain; format=flowed; charset="iso-8859-2"; reply-type=response
Content-Transfer-Encoding: 8bit
X-Trace: inews.gazeta.pl 1271177896 5103 89.73.79.1 (13 Apr 2010 16:58:16 GMT)
X-Complaints-To: u...@a...pl
NNTP-Posting-Date: Tue, 13 Apr 2010 16:58:16 +0000 (UTC)
X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.5579
X-Priority: 3
X-Newsreader: Microsoft Outlook Express 6.00.2900.5843
X-User: robakks
X-MSMail-Priority: Normal
Xref: news-archive.icm.edu.pl pl.sci.filozofia:202289 pl.sci.inzynieria:26488
[ ukryj nagłówki ]
Odcinek o długości 1 metr ma continuum punktów o długości
pkt = 1/C = 1metr / continuum
Dwa punkty mają dwa razy większą długość niż jeden punkt.
Napisz co zrozumiałeś. OK?
Robakks
*°"˝'´¨˘`˙.^:;~>¤<×÷-.,˛¸